Hi guys, welcome to today’s tutorial!
Today, we’ll be looking at possible 2026 JAMB Mathematics questions and how to solve them step-by-step. Let’s dive into the questions and concepts.
You can watch the full class in the video below:
Question 1: Permutations with Repeated Letters
Question:
How many different eight-letter words are possible using the letters of the word “syllables”?
Solution:
The word syllables contains the following letter counts:
- S = 2
- Y = 1
- L = 2
- A = 1
- B = 1
- U = 1
To find the number of different eight-letter words, we use the formula for permutations of repeated items: 8!2!×2!\frac{8!}{2! \times 2!}2!×2!8!
So the correct option is Option C.
Question 2: Laws of Indices
Question:
Evaluate: 160.16×160.04×20.216^{0.16} \times 16^{0.04} \times 2^{0.2}160.16×160.04×20.2
Solution:
First, express 16 as a power of 2: 16=2416 = 2^416=24
So we substitute: 24×0.16×24×0.04×20.22^{4 \times 0.16} \times 2^{4 \times 0.04} \times 2^{0.2}24×0.16×24×0.04×20.2
This becomes: 20.64×20.16×20.22^{0.64} \times 2^{0.16} \times 2^{0.2}20.64×20.16×20.2
Using the law of indices ax×ay=ax+ya^x \times a^y = a^{x+y}ax×ay=ax+y: 20.64+0.16+0.2=21=22^{0.64 + 0.16 + 0.2} = 2^1 = 220.64+0.16+0.2=21=2
Answer: Option A.
Question 3: Binary Operations
Given:
Let * and # be two binary operations such that:
- a∗b=a2ba * b = a^2 ba∗b=a2b
- a#b=2a+ba \# b = 2a + ba#b=2a+b
Find:
Evaluate −4∗7#−1-4 * 7 \# -1−4∗7#−1
(Note: The question cuts off here, but the solution involves evaluating the binary operations using their definitions.
Watch more educational videos and past questions: https://youtube.com/@allcbts
Suggested Internal Links:
- [JAMB 2026 English Questions and Solutions]
- [Top 100 Likely JAMB Maths Questions]
- [Free CBT Practice Platform – AllCBTs]
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“Ace JAMB 2026 Mathematics with these expertly solved questions on permutations, indices, and binary operations. Learn faster with this humanized breakdown and clear logic. Perfect for your CBT prep!”
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