WAEC 2024 Mathematics Past Questions Solved.

Welcome to today’s mathematics tutorial!
In this lesson, we will solve and break down real WAEC 2024 Mathematics past questions. Be sure to grab your writing materials and calculator, because these questions are packed with exam-smart concepts you’ll need to pass WAEC in one sitting!

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You can watch the full class in the video below:

Question 1: Multiply 3.44×10−53.44 \times 10^{-5}3.44×10−5 by 7.1×1087.1 \times 10^87.1×108

This is a multiplication of numbers in standard form. We apply the laws of indices:

Step 1: Multiply the base numbers

3.44×7.1=24.4243.44 \times 7.1 = 24.4243.44×7.1=24.424

Step 2: Add the powers of 10

10−5×108=108−5=10310^{-5} \times 10^8 = 10^{8 – 5} = 10^310−5×108=108−5=103

So the product becomes: 24.424×10324.424 \times 10^324.424×103

Step 3: Convert to standard form

The decimal should be between the first and second digit: 2.4424×1042.4424 \times 10^42.4424×104

Correct Option: C

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Question 2: Given Sets

Let P={1<P<20}P = \{1 < P < 20\}P={1<P<20} where P is an integer, and
Let R={0<R≤25}R = \{0 < R \leq 25\}R={0<R≤25} where R is a multiple of 4.

Find: P∩RP \cap RP∩R

Step 1: List elements in P
Integers strictly between 1 and 20: P={2,3,4,5,…,19}P = \{2, 3, 4, 5, …, 19\}P={2,3,4,5,…,19}

Step 2: List elements in R (multiples of 4) R={4,8,12,16,20,24}R = \{4, 8, 12, 16, 20, 24\}R={4,8,12,16,20,24}

Step 3: Intersection of P and R
Common elements = {4, 8, 12, 16}

Correct Option: B

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Question 3: Arithmetic Progression

The first term a=2a = 2a=2, the last term l=29l = 29l=29, and the common difference d=3d = 3d=3.

Find: Number of terms nnn

Use the formula: Tn=a+(n−1)dT_n = a + (n – 1)dTn​=a+(n−1)d

Substitute: 29=2+(n−1)×329 = 2 + (n – 1) \times 329=2+(n−1)×3 29=2+3n−3⇒29=3n−1⇒30=3n⇒n=1029 = 2 + 3n – 3 \Rightarrow 29 = 3n – 1 \Rightarrow 30 = 3n \Rightarrow n = 1029=2+3n−3⇒29=3n−1⇒30=3n⇒n=10

Correct Option: C
There are 10 terms in the sequence.

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Question 4: Express in Index Form

Given: log⁡ax+log⁡ay=3\log_a x + \log_a y = 3loga​x+loga​y=3

Using the logarithm rule: log⁡ax+log⁡ay=log⁡a(xy)\log_a x + \log_a y = \log_a (xy)loga​x+loga​y=loga​(xy)

So: log⁡a(xy)=3\log_a (xy) = 3loga​(xy)=3

Convert to index form: xy=a3xy = a^3xy=a3

Final Expression: xy=a3xy = a^3xy=a3

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Watch more educational videos and past questions: https://youtube.com/@allcbts

Final Takeaways

• When multiplying standard form numbers, multiply the numbers, then add the indices.
• Understand set notation and how to find intersections clearly.
• For arithmetic sequences, know how to use the nth term formula to find missing values.
• Master the laws of logarithms and how to convert logs to indices.

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