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JAMB 2026 Mathematics Questions.

JAMB 2026 Mathematics Questions.

Published on Jul 16, 2025 β€’ Education

In this blog post, we explore likely Mathematics questions for JAMB 2026, breaking down each problem with a step-by-step solution. Whether you're brushing up for UTME or targeting high scores, these worked examples will give you the clarity and confidence you need.


You can watch the full class in the video below:

https://www.youtube.com/watch?v=j7x0cTce8O8&t=15s

Question 1: Permutation with Repeated Letters

Question:
How many different 8-letter words can be formed from the word SYLLABLES?

Solution:
First, analyze the frequency of the letters in "SYLLABLES":

  • S = 2
  • Y = 1
  • L = 2
  • A = 1
  • B = 1
  • E = 1

To calculate the total number of unique arrangements with repeated letters: TotalΒ permutations=8!2!Γ—2!\text{Total permutations} = \frac{8!}{2! \times 2!}TotalΒ permutations=2!Γ—2!8!​

This accounts for the repeated S and L.

Answer: Option C


Question 2: Indices Simplification

Question:
Evaluate 160.16Γ—160.04Γ—20.216^{0.16} \times 16^{0.04} \times 2^{0.2}160.16Γ—160.04Γ—20.2

Solution:

Step 1: Express 16 as a power of 2: 16=2416 = 2^416=24

So, (24)0.16=20.64,(24)0.04=20.16(2^4)^{0.16} = 2^{0.64}, \quad (2^4)^{0.04} = 2^{0.16}(24)0.16=20.64,(24)0.04=20.16

Now multiply: 20.64Γ—20.16Γ—20.2=20.64+0.16+0.2=21=22^{0.64} \times 2^{0.16} \times 2^{0.2} = 2^{0.64 + 0.16 + 0.2} = 2^1 = 220.64Γ—20.16Γ—20.2=20.64+0.16+0.2=21=2

Answer: Option A


Question 3: Binary Operations

Question:
Let * and ∘ be two binary operations defined as follows:

  • aβˆ—b=a2β‹…ba * b = a^2 \cdot baβˆ—b=a2β‹…b
  • a∘b=2a+ba \circ b = 2a + ba∘b=2a+b

Find the value of: (βˆ’4βˆ—2)∘(7βˆ—βˆ’1)(-4 * 2) \circ (7 * -1)(βˆ’4βˆ—2)∘(7βˆ—βˆ’1)

Step 1: Solve βˆ’4βˆ—2-4 * 2βˆ’4βˆ—2

(βˆ’4)2β‹…2=16β‹…2=32(-4)^2 \cdot 2 = 16 \cdot 2 = 32(βˆ’4)2β‹…2=16β‹…2=32

Step 2: Solve 7βˆ—βˆ’17 * -17βˆ—βˆ’1

72β‹…(βˆ’1)=49β‹…βˆ’1=βˆ’497^2 \cdot (-1) = 49 \cdot -1 = -4972β‹…(βˆ’1)=49β‹…βˆ’1=βˆ’49

Step 3: Combine using ∘ operation:

32βˆ˜βˆ’49=2β‹…32+(βˆ’49)=64βˆ’49=1532 \circ -49 = 2 \cdot 32 + (-49) = 64 - 49 = 1532βˆ˜βˆ’49=2β‹…32+(βˆ’49)=64βˆ’49=15

Answer: 15


Watch more educational videos and past questions: https://youtube.com/@allcbts


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Explore fully worked solutions to JAMB 2026 likely math questions, including permutations, indices, binary operations, and more. Ideal for UTME preparation.

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